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[xsl] Re: adding column number to the entry

From: List Owner <xsl-list-owner@-----.------------.--->
To: xsl-list@-----.------------.---
Date: 9/3/2009 12:21:00 PM
If you find that your question on XSL-List does not get answered, or 
that the answers provided do not meet your need, make it easier for 
people to answer the question by clarifying it and/or providing more 
information.

In your case, I suggest two things:

   1. provide the smallest possible example that illustrates your
      question. (it looks to me like there is a lot of "clutter" in
      your example; for example cell names and columnspans are not
      needed to deal with the question you asked)

   2. in addition to a small example describe in words, where the
      information in the desired result would come from in the
      input. Is it the case that you want RowSpan to equal 1
      unless the value of the cell element is longer than 16
      characters? Or is there some other logic that you want
      implemented in your XSLT?

Please re-post your question, with a more targeted example and a 
description of what you are trying to accomplish.

-- Tommie


At 3:07 PM +0530 9/3/09, Ganesh Babu N wrote:
>Please help me on this issue.
>
>Regards,
>Ganesh
>
>On Tue, Sep 1, 2009 at 3:09 PM, Ganesh Babu N<nbabuganesh@g...> wrote:
>  > Dear All,
>>
>>  I am having a input like this.
>>
>>  <table>
>>         <row>
>>                 <entry align="left" valign="top">Table 1 TB C1 R5</entry>
>>                 <entry align="left" valign="top" morerows="1">Table 
>>1 TB C2 R5 and
>>  TB C2 R6 are merged</entry>
>>                 <entry align="left" valign="top">Table 1 TB C3 R5</entry>
>>                 <entry align="left" valign="top">Table 1 TB C4 R5</entry>
>>         </row>
>>         <row>
>>                 <entry align="left" valign="top">Table 1 TB C1 R6</entry>
>>                 <entry align="left" valign="top">Table 1 TB C3 R6</entry>
>>                 <entry align="left" valign="top">Table 1 TB C4 R6</entry>
>>         </row>
>>  </table>
>>
>>  My required output is as follows:
>>
>>  <table>
>>    <cell Name="1" RowSpan="1" ColumnSpan="1">Table 1 TB C1 R5</cell>
>>    <cell Name="2" RowSpan="2" ColumnSpan="1">Table 1 TB C2 R5 and TB
>>  C2 R6 are merged</cell>
>>    <cell Name="3" RowSpan="1" ColumnSpan="1">Table 1 TB C3 R5</cell>
>>    <cell Name="4" RowSpan="1" ColumnSpan="1">Table 1 TB C4 R5</cell>
>>    <cell Name="1" RowSpan="1" ColumnSpan="1">Table 1 TB C1 R6</cell>
>>    <cell Name="3" RowSpan="1" ColumnSpan="1">Table 1 TB C3 R6</cell>
>>    <cell Name="4" RowSpan="1" ColumnSpan="1">Table 1 TB C4 R6</cell>
>>  </table>
>>
>>  I have tried with the following code but it is changing the number in
>>  all the 2nd row entries. It requires to be changed only in C3 of R6
>>  and C4 of R6. Because C2 of R6 is already merged with C2 of R5.
>>
>>  <xsl:template match="entry>
>>       <xsl:if test="parent::row/preceding-sibling::row/entry/@morerows">
>>            <xsl:value-of select="position() +
>>  parent::row/preceding-sibling::row/entry[@morerows]/position()"/>
>>       </xsl:if>
>>  </xsl:template>
>>
>>  Please help me getting required output.
>>
>>  Regards,
>>  Ganesh
>>

-- 

======================================================================
B. Tommie Usdin                        mailto:btusdin@m...
Mulberry Technologies, Inc.                http://www.mulberrytech.com
17 West Jefferson Street                           Phone: 301/315-9631
Suite 207                                    Direct Line: 301/315-9634
Rockville, MD  20850                                 Fax: 301/315-8285
----------------------------------------------------------------------
   Mulberry Technologies: A Consultancy Specializing in XML and SGML
======================================================================

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