Altova Mailing List Archives>Archive Index >xsl-list Archive Home >Recent entries >Thread Prev - [xsl] Determining whether no single instance of a specific node >Thread Next - Re: [xsl] Determining whether no single instance of a specific node RE: [xsl] Determining whether no single instance of a specific nodeTo: <xsl-list@-----.------------.---> Date: 6/4/2009 6:52:00 PM Hello,
<xsl: if test="not(exists( (b/c) ) )" > ... </xsl:if>
Check other functions here:
http://www.w3schools.com/xpath/xpath_functions.asp#sequence
You can use all xpath functions in the if/when test condition.
m.
-----Original Message-----
From: Mark Peters [mailto:markpeters.work@g...]
Sent: 4. júna 2009 20:21
To: xsl-list@l...
Subject: [xsl] Determining whether no single instance of a specific node
exists
Hi Everyone,
I have the following XML document:
<a>
<b/>
<b/>
<b/>
</a>
<a>
<b/>
<b/>
<b>
<c/>
</b>
</a>
<a>
<b/>
<b/>
<b/>
</a>
For each <b/> set, I want to apply a transformation only if no single
instance of <c/> exists. I know how to check whether a node does
exist, but not how to check whether no single instance of the node
exists.
I've tried the following conditional statements without success:
1,
<xsl:when test="not(a/b/c)">
2.
<xsl:when test="count(not(a/b/c)) >= 1">
What conditional statement should I use?
Thanks in advance for any help.
Mark
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