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| | | Altova Mailing List Archives>Archive Index >xsl-list Archive Home >Recent entries >Thread Prev - [xsl] Looping through a tree and retaining parent values [Thread Next] RE: [xsl] Looping through a tree and retaining parent valuesTo: Date: 4/1/2009 2:27:00 PM Hello,
This should work:
<xsl:output indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<body>
<xsl:apply-templates/>
</body>
</xsl:template>
<xsl:template match="menuItems">
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="menuItem">
<p id="{@label}">
<xsl:apply-templates select="ancestor-or-self::menuItem" mode="uic"/>
</p>
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="menuItem" mode="uic">
<uicontrol>
<xsl:value-of select="@label"/>
</uicontrol>
</xsl:template>
What this does is, for every menuItem in the source,
creates a p element, then populates it with all ancestors
of the current menuItem (including itself) renamed as
uicontrol and having the @label as content.
Regards,
EB
> -----Original Message-----
> From: Mark Peters [mailto:flickrmeister@xxxxxxxxx]
> Sent: Wednesday, April 01, 2009 3:58 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Looping through a tree and retaining parent values
>
>
> Hi Everyone,
>
> I'm puzzling over a transformation that I thought would be simple but
> which becomes progressively more complex as I try to wrap my mind
> around it.
>
> Here is a series of menuItem nodes, which are nested in menuItems
> nodes. Each menuItem node has a label attribute.
>
> <menuConfig>
> <menu id="A">
> <menuItems>
> <menuItem label="1">
> <menuItems>
> <menuItem label="a"/>
> <menuItems>
> <menuItem
> label="1a">
> <menuItems>
>
> <menuItem label="1a.a"/>
>
> <menuItem label="1a.b"/>
> </menuItems>
> </menuItem>
> </menuItems>
> <menuItem label="b">
> </menuItem>
> </menuItems>
> </menuItem>
> <menuItem label="2">
> <menuItems>
> <menuItem label="c"/>
> <menuItem label="d">
> <menuItems>
> <menuItem
> label="2d">
> <menuItems>
>
> <menuItem label="2d.d"/>
>
> <menuItem label="2d.e"/>
>
> <menuItem label="2d.f"/>
> </menuItems>
> </menuItem>
>
> </menuItems>
> </menuItem>
> <menuItem label="e">
> <menuItems>
> <menuItem
> label="2e">
> <menuItems>
>
> <menuItem label="2e.g"/>
> </menuItems>
> </menuItem>
> </menuItems>
> </menuItem>
> </menuItems>
> </menuItem>
> </menuItems>
> </menu>
> </menuConfig>
>
> What I'm trying to do is create a set of p nodes which nest a series
> of uicontrol nodes, one uicontrol node for each level of menuItem in
> the original XML document. In other words, for each menuItem in the
> original XML, there should be a uicontrol element. The first uicontrol
> node in the series contains the @label value for the parent menuItem
> node. The next uiconcontrol node in the series contains the @label
> value for the first child menuItem node, and so on.
>
> The p node should have an id attribute whose value is the @label value
> of the last child node in each tree.
>
> Here is an example:
>
> <body>
> <p id="1">
> <uicontrol>1</uicontrol>
> </p>
> <p id="a">
> <uicontrol>1</uicontrol> >
> <uicontrol>a</uicontrol></p>
> <p id="1a">
> <uicontrol>1</uicontrol> >
> <uicontrol>a</uicontrol> >
> <uicontrol>1a</uicontrol>
> </p>
> <p id="1.1a">
> <uicontrol>1</uicontrol> >
> <uicontrol>a</uicontrol> >
> <uicontrol>1a</uicontrol> >
> <uicontrol>1a.a</uicontrol>
> </p>
> <p id="1.1b">
> <uicontrol>1</uicontrol> >
> <uicontrol>a</uicontrol> >
> <uicontrol>1a</uicontrol> >
> <uicontrol>1b.b</uicontrol>
> </p>
> <p id="b">
> <uicontrol>1</uicontrol> >
> <uicontrol>b</uicontrol>
> </p>
> <p id="2">
> <uicontrol>2</uicontrol>
> <p id="c">
> <uicontrol>2</uicontrol> >
> <uicontrol>c</uicontrol>
> </p>
> <p id="d">
> <uicontrol>2</uicontrol> >
> <uicontrol>d</uicontrol>
> </p>
> <p id="2d">
> <uicontrol>2</uicontrol> >
> <uicontrol>d</uicontrol> >
> <uicontrol>2d</uicontrol>
> </p>
> <p id="2d.d">
> <uicontrol>2</uicontrol> >
> <uicontrol>d</uicontrol> >
> <uicontrol>2d</uicontrol> >
> <uicontrol>2d.d</uicontrol>
> </p>
> <p id="2d.e">
> <uicontrol>2</uicontrol> >
> <uicontrol>d</uicontrol> >
> <uicontrol>2d</uicontrol> >
> <uicontrol>2d.e</uicontrol>
> </p>
> <p id="e">
> <uicontrol>2</uicontrol> >
> <uicontrol>e</uicontrol>
> </p>
> <p id="2e">
> <uicontrol>2</uicontrol> >
> <uicontrol>e</uicontrol> >
> <uicontrol>2e</uicontrol></p>
> <p id="2e.g">
> <uicontrol>2</uicontrol> >
> <uicontrol>e</uicontrol> >
> <uicontrol>2e</uicontrol> >
> <uicontrol>2e.g</uicontrol>
> </p>
> </body>
>
> So far, I've come up with a stylesheet that produces a single p node
> for every parent menuItem. It's a start. I've thought about trying to
> use variables to retain the menuItem/@label values at each level in
> the tree; but, reading about variables, I'm not sure this is possible.
> Likewise, I've thought about defining each loop in a separate template
> and then calling each template from the "master" template. But then,
> I'm not sure how I'd retrieve the final menuItem/@label value for the
> p/@id value.
>
> And I must not understand the last() function correctly. The p/@id
> values inserted by the stylesheet are "1a" and "2e.g," and not the
> @label value for the last menuItem in each tree.
>
> <xsl:template match="/">
> <xsl:for-each select="//menu">
> <body>
> <xsl:for-each select="menuItems">
> <xsl:for-each select="menuItem">
> <p>
>
> <xsl:attribute name="id">
>
> <xsl:value-of select="descendant::menuItem[last()]/@label"/>
> </xsl:attribute>
> <uicontrol>
>
> <xsl:value-of select="@label"/>
> </uicontrol> >
>
> <xsl:for-each select="descendant::menuItem[2]">
> <uicontrol>
>
> <xsl:value-of select="@label"/>
>
> </uicontrol> >
>
> <xsl:for-each select="descendant::menuItem[3]">
>
> <uicontrol>
>
> <xsl:value-of select="@label"/>
>
> </uicontrol> >
>
> <xsl:for-each select="descendant::menuItem[4]">
>
> <uicontrol>
>
> <xsl:value-of select="@label"/>
>
> </uicontrol> >
>
> <xsl:for-each select="descendant::menuItem[5]">
>
> <uicontrol>
>
> <xsl:value-of select="@label"/>
>
> </uicontrol> >
>
> </xsl:for-each>
>
> </xsl:for-each>
>
> </xsl:for-each>
> </xsl:for-each>
> </p>
> </xsl:for-each>
> </xsl:for-each>
> </body>
> </xsl:for-each>
> </xsl:template>
>
> I'd appreciate any help you could offer.
>
> Thanks,
> Mark
> --
>
> Mark Peters
> Senior Technical Writer
> Saba Software | |
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