At 2008-12-31 12:47 -0800, Kit Strong wrote:
I need a bit of help with count() as so far I've
been unable to construct a valid expression to obtain what  I need
Basically
what I'm trying to do is generate Table numbers relative to Chapters but only
for tables that contain a title element.  Here's an example
structure


<chapter>
    <p>...</p>
    <table
class="topic/table">
        <title class="table/title">(should
resolve to Table 1.1) ...<title>
        ...

</table>
     <table class="topic/table>...</table>

<section>
       <table> ...</table>

<table>
            <title class="table/title">(should resolve to
Table 1.2) ...<title>
            ...
        </table>
    </chapter>
<chapter>
    <table
class="topic/table>>...</table>
    <section>

<p>
            <table class="topic/table">

<title class="table/title">Should resolve to Table 2.1
</title>
                ...
            </table>

</p>
    </section>
</chapter>

Getting the

chapter number is easy enough 'count(preceding::chapter)+1' but what 
I'm having

problems with is the Table number in relation to the chapter

I can get the

Table position in relation to the document

via

select="count(preceding::*[contains(@class,' topic/table

')]/*[contains(@class,' topic/title ')])+1"

but I'm not quite sure how to

combine the 2 expressions to give me the proper count in relationship to the

current <chapter>



Any help would be much appreciated.

I think you should just use what you need along the lines of the following:



   <xsl:number count="*[contains(@class,' topic/table ')]
                      [*[contains(@class,' topic/title ')]]"
               from="chapter" level="any"/>

... instead of using count().  The from= limits the count to those 
items below the closest matching ancestor.



Note also that I'm counting tables qualified by their title ... in 
your code you were counting the table titles.  Probably the same in 
this case, but semantically I'm counting tables in case that helps 
for maintenance and understanding.



I hope this helps.



. . . . . . . . . . . Ken



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