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[xsl] XSLT 2.0 replace()

From: Lou Iorio <lou@------------>
To:
Date: 9/2/2008 1:19:00 PM

Just learning XSLT 2.0 (and regex), and I'm stumped on the replace()  
function.



I have XML that looks like this:



<toc>

   <category title="Structure">

       <item title="&amp;lt;attribute&amp;gt;"   
href="tag.attribute.html" />

       <item title="&amp;lt;handler&amp;gt;" href="LzDelegate.html" />

       <item title="&amp;lt;event&amp;gt;" href="LzEvent.html" />

	.

	.

	.



And I want to replace the &amp; with just &, so the HTML that looks  
like this:



 <body>
     <h1>nav toc</h1>
     <ol>
        <li>Structure</li>
        <ol>
           <li>&lt;lattribute&gt;</li>
           <li>&lt;handler&gt;</li>
           <li>&lt;event&gt;</li>

The closed I've been able to get is this:



  <body>
     <h1>nav toc</h1>
     <ol>
        <li>Structure</li>
        <ol>
           <li>&lt;attribute&amp;gt;</li>
           <li>&lt;handler&amp;gt;</li>
           <li>&lt;event&amp;gt;</li>

So I can change the first &amp;, but not the second. Any ideas? I feel  
like I

must be missing a fundamental concept here.



Here's a fragment of my XSLT:



       <ol>

         <xsl:for-each select="category">

           <li>

             <xsl:value-of select="@title"/>

           </li>

           <ol>

             <xsl:for-each select="item">

               <li>

                 <xsl:value-of select="replace(@title, '&amp;lt;',  
'&lt;')"/>

               </li>

             </xsl:for-each>

           </ol>

         </xsl:for-each>

       </ol>



thanks,



Lou

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[xsl] XSLT 2.0 replace()