Hi Vaduvoiu



Your test is always false, unless the text itself is only a space. 
Change it to:



<xsl:when test="substring($text,$length-1, 1)=' ' ">



and you should be fine.



Note that in XSLT 2.0 you can do this with replace($text, ' [^ ]*', ''), which is a little bit shorter than your 14 lines, but you didn't mention whether you could use XSLT 2.0



If the strings get quite large, consider optimizing your template (if in XSLT 1.0, I mean) with substring-before.



Cheers,



-- Abel Braaksma








Vaduvoiu Tiberiu wrote:
Hi, i'm trying to do the following thing: I need to display a string until the last occurance of the space character.So if I would have "this is a news" i would need to display "this is a". I am using xslt1.0 and I tried doing the following:



<xsl:template name="extract">
<xsl:param name="text"/>
<xsl:variable name="length" select="string-length($text)"/>
<xsl:choose>
    <xsl:when test="substring($text,$length-1,$length)=' ' ">
        <xsl:value-of select="substring($text,1,$length-1)"/>
    </xsl:when>
<xsl:otherwise>
    <xsl:call-template name="extract">
        <xsl:with-param name="text" select="substring($text,1,$length-1)"/>
    </xsl:call-template>
</xsl:otherwise>
</xsl:choose>
</xsl:template>

basically I check if the last char of the string is space, display the text minus last char, otherwise, test again with text minus the last char. I get the error 
Error during XSLT transformation: XSLT Stylesheet (possibly) contains a recursion. I don't see why it would be interpreted as a infinit loop since the text keeps getting smaller.




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