There are a few options, with your current style use <xsl:value-of 
select="../Name"/>, the .. means use the parent, Customer, then choose the 
child Name. I think a better way would be to select only the Customer 
elements with a status: <xsl:for-each select="Customers/Customer[Status]"> 
to start with then just output Name and Status.



Joe
http://joe.fawcett.name



From: "Waqar Ali" <waqarali_pk@xxxxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: [xsl] XSL Help
Date: Mon, 01 Oct 2007 11:31:17 -0400

<Customers>
	<Customer>
		<Name>Joe Smith</Name>
		<Status>VIP</Status>
	</Customer>
	<Customer>
		<Name>Mary J</Name>
	</Customer>
	<Customer>
		<Name>John Hopkins</Name>
		<Status>VVIP</Status>
	</Customer>
</Customers>

Generate a list of records with Status:
	<xsl:template name="SPECIAL" match="/">
		<xsl:for-each select="Customers/Customer/Status">
			<xsl:value-of select="/Name"/>
			<xsl:text>-</xsl:text>
			<xsl:value-of select="/Status"/>
		</xsl:for-each>
	</xsl:template>

The names/status are not getting printed. How can I move one level up to 
print

the names using value-of.



Desired Output:
	Joe Smith-VIP
	John Hopkins-VVIP