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[xsl] Output as per the filter is missing

From: "Sharma, Jaikumar" <jaikumar.sharma@--------->
To:
Date: 8/1/2007 7:44:00 AM
Hi All,

I have the following XML document and XSL stylesheet.

Problem : When I try to render the XML document in HTML using browser.
It gives me the following output, but does not list all the warning
messages as per the filter in XSL stylesheet, it only list the first
warning message.

Output :
___________________________
Test Page

warn message 1
____________________________


XML document :
__________________________________________________________
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="test.xsl"?>
<docroot>
   <mydocument>
     <para>
        <section>
             <message priority="warn">warn message 1</message>
             <message priority="warn">warn message 2</message>
             <message priority="info">info message 1</message>
             <message priority="info">info message 2</message>
             <message priority="info">info message 3</message>

        </section>
     </para>
   </mydocument>
</docroot>
__________________________________________________________

XSL stylesheet :

_________________________________________________________
<?xml version="1.0"?>
  <xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="html" indent="yes" />

  <xsl:template match="/">
    <html>
      <head><p><b>Test Page</b></p></head>
       <body>
         <xsl:apply-templates select="docroot/mydocument/para"/>
       </body>
    </html>
  </xsl:template>

   <xsl:template match="*">
    <xsl:for-each select="section">
          <xsl:value-of select="message[@priority='warn']"/>
    </xsl:for-each>
   </xsl:template>

 </xsl:stylesheet>

_______________________________________________________


I am Newbie to XSL, does somebody know which step I am missing here ?

Thanks.


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