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[xsl] Finding the current node type

From: "Mark Anderson" <mark.anderson@------------------->
To:
Date: 8/1/2007 1:39:00 PM
Thanks Guys

In my application, I will only need to process a few hundred nodes and
about 20-30 of the type where I need to use the choose statement.

I went with the <xsl:if test=self::speaker> option as I still use the
namespace (e.g. <xsl:if test=self::abc:speaker>). Whereas localname
returned the node name without the ns prefix

Thanks for the help

Regards

mark


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