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Re: [xsl] Finding the current node type

From: Abel Braaksma <abel.online@--------->
To:
Date: 8/1/2007 2:14:00 PM
Mark Anderson wrote:
Thanks Guys



In my application, I will only need to process a few hundred nodes and

about 20-30 of the type where I need to use the choose statement.

  

??

Sounds like you want a copy idiom with some template matches instead of 
xsl:choose (or remove the copy if you meant with the above that you want 
to remove all the things not in the xsl:choose)



I went with the <xsl:if test=self::speaker> option as I still use the

namespace (e.g. <xsl:if test=self::abc:speaker>). Whereas localname

returned the node name without the ns prefix

  

Correct, as already been stated in this thread. If you find yourself 
doing test="self::ns:speaker" or similar, it is almost always better to 
do xsl:apply-templates with xsl:template matching. XSLT code only rarely 
really needs xsl:choose or xsl:if statements. Note that apply-templates 
automatically does nothing when the selected node set is not there.



Cheers,
-- Abel Braaksma


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