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[xsl] Accessing attribute in a variable with conditional value

From: "Wasiq Shaikh" <wasiq911@----------->
To:
Date: 8/1/2007 5:42:00 PM
Hi,



I'm setting a value on a variable using conditions. The variable must be a 
node-set so that I can do some processing with it.



     <xsl:variable name="validAttributeType">
        <xsl:if test="key('allTypes', @type)">
           <xsl:copy-of select="key('allTypes', @type)/xsd:restriction"/>
        </xsl:if>
        <xsl:if test="xsd:simpleType"
           <xsl:copy-of select="xsd:simpleType/xsd:restriction"/>
        </xsl:if>
     </xsl:variable>

The "xsd:restriction" tag has a "base" attribute that I need to access and 
send to a template as a parameter.



           <xsl:call-template name="trimAttribute">

              <xsl:with-param name="attributeName" select="'base'"/>

              <xsl:with-param name="attribute" 
select="$validAttributeType/@base"/>

           </xsl:call-template>



But it gives me a "XSLT Error (javax.xml.transform.TransformerException): 
org.apache.xpath.objects.XRTreeFrag" when I try to do



<xsl:with-param name="attribute" select="$validAttributeType/@base"/>

OR

<xsl:with-param name="attribute"><xsl:copy-of 
select="$validAttributeType/@base"/></xsl:with-param>



I can print out the variable's contents, which is correct, but I can't seem 
to access the attribute. By the way, previously I had this



<xsl:variable name="validAttributeType" select="key('allTypes', 
@type)/xsd:restriction"/>



which works! But adding the conditional messed it up. How can I get the same 
behaviour as the above line in a conditional variable?



I appreciate any help. Thank you!



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