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![]() | ![]() | ![]() | Altova Mailing List Archives>Archive Index >xsl-list Archive Home >Recent entries >Thread Prev - [xsl] xsl:element will not create an output element, in any context [Thread Next] Re: [xsl] xsl:element will not create an output element, in any contextTo: Date: 6/1/2007 12:13:00 PM Legend, thanks mate.
Thanks to Michael too =)
- Dave
David Carlisle wrote:
However, using elements:
<xsl:element name="xhtml:ul">
...
</xsl:element>
Produces '<xhtml:ul>...</xhtml:ul>' in the output XML.
which (assuming you have the right namespace bound to xhtml:) is the
same thing, and it will render correctly in a system that is rendering
xhtml (eg firefox or opera, if you are serving it as
application/xhtml+xml) However it isn't DTD-valid (because DTD don't
know about namespaces) and it won't render on a system like IE which
knows nothing about XHTML and just renders the file as HTML by ignoring
small syntactic differences like /> empty element syntax, but falling
over large syntactic differences like prefixes.
David
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