>Archive Index
>xsl-list Archive Home
>Recent entries

>Thread Prev - RE: [xsl] Xsl:copy-of writes xmlns:xsi always - Any way to avoid this?
[Thread Next]

Re: [xsl] Xsl:copy-of writes xmlns:xsi always - Any way to avoid this?

From: Abel Braaksma <abel.online@--------->
To:
Date: 3/5/2007 10:09:00 AM

binu.idicula@xxxxxxxxx wrote:
I used the following .. But the problem was that it is not copying

nested. 
It just copies the direct chile element nodes. If the child element has

another child, do I have to write one more for-each OR is there a simple

way.



            <xsl:for-each select="./*">
                <xsl:element name="{name()}"
namespace="{namespace-uri()}">
                <xsl:copy-of select="@*"/>
                <xsl:apply-templates/>
            </xsl:element>
            </xsl:for-each>

Once I select a particular node, all the contents (including next level
- children) should be translated to another XML. Please advice

Michael was not talking of a for-each loop, which only walks through the 
selected node set. He meant (and gave an example of) a modified identity 
template which is the generic way of processing an input tree and modify 
only small parts of it. Use template matches instead of for-each to 
achieve that effect (see Michaels original answer).

>Thread Prev - RE: [xsl] Xsl:copy-of writes xmlns:xsi always - Any way to avoid this?
[Thread Next]

>Archive Index
>xsl-list Archive Home
>Recent entries

Altova Mailing List Archives

Re: [xsl] Xsl:copy-of writes xmlns:xsi always - Any way to avoid this?