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Re: [xsl] Creating Nested Structure Based on Attributes

From: Jeff Sese <jsese@------------>
Date: 3/20/2007 8:20:00 AM
Thanks, Abel and David.

Both works well, but i think i'll go with abel's solution because i'm 
using xslt 2.0.

*Jeff Sese*

Abel Braaksma wrote:
Jeff Sese wrote:

<inline font-style="italic" font-variant="small-caps" 
font-weight="bold" vertical-alignment="superscript">text</inline>

Hi Jeff,

David Carlisle already showed you how to do it in XSLT 1.0 with mode 
switching. I don't know if you have the possibility to use XSLT 2.0, 
but here's a solution that does the same in XSLT 2.0, with the help of 
a little function that turns any range of attributes into a 
hierarchical node list, making it easier to use with matching 
templates. It's perhaps a bit non-conventional, but it keeps your code 
pretty tight.

Output from your source is equal to the requested output.

Happy coding!

-- Abel Braaksma


   <xsl:output indent="yes" />

   <xsl:template match="inline">


select="f:attr-to-nodes-hier(attribute::*, text())" />



   <!-- result from f:attr-to-nodes-hier -->

   <xsl:template match="attr">

       <emphasis format="{@value}">

           <xsl:apply-templates select="node()" />



     <!-- result from f:attr-to-nodes-hier -->

   <xsl:template match="attr[@name = 'vertical-alignment']">


           <xsl:apply-templates select="node()" />



     <xsl:function name="f:attr-to-nodes-hier" as="node()*">

       <xsl:param name="attributes" as="attribute()*" />

       <xsl:param name="text" as="text()" />

       <xsl:if test="$attributes">

           <attr name="{$attributes[1]/name()}" value="{$attributes[1]}">

select="f:attr-to-nodes-hier($attributes[position() > 1], $text)" />



       <xsl:if test="empty($attributes)">

           <xsl:sequence select="$text" />

       </xsl:if>              </xsl:function>



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