Hi all,

 Thanks for the reply.  I actually got this resolved.  I really appreciate 
your help.

I made a mistake in my code.

Thanks,

Sola









From: Abel Braaksma <abel.online@xxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Using xsl:sort to sort negative values
Date: Tue, 20 Feb 2007 23:09:46 +0100

Hi Sola,



You didn't show your full code and you didn't tell what processor you are 
using and what XSLT version. If you specifiy "number" for the data-type, 
then the content is converted to a numeric value. This includes the minus 
sign.



Note that your data is illegal XML as where legal XML it is not allowed to 
have any element starting with xml, XML or any combination of case, see 
http://www.w3.org/TR/xml/#IDAKKFS. However, most XML processors dig it 
anyway ;)



I tried the following stylesheet and ran it with Saxon 8. It gives the 
result you want:



<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

     <xsl:output indent="yes" />

     <xsl:template match="/xml">

       <xsl:apply-templates select="data">

          <xsl:sort select="." data-type="number" />

       </xsl:apply-templates>

   </xsl:template>

     <xsl:template match="data">

       <xsl:text>
</xsl:text>
       <xsl:value-of select="text()"/>
   </xsl:template>
  </xsl:stylesheet>


If this does not work with your processor, it is likely a bug.



Good luck with it,



Cheers,
-- Abel





Sola Awe wrote:
Hi,
  Can anyone tell why the code below will not work?

<xsl:sort select="data" data-type="number"/>



I am trying to sort numeric data that contains negative values but the 
order seems to be wrong



<xml>
<data>22</data>
<data>2</data>
<data>-5</data>
<data>42</data>
<data>0</data>
<data>-1</data>
<data>0</data>
</xml>


This is the output



0
-1
0
-5
2
22
42

I want
-5
-1
0
0
2
22
42