Altova Mailing List Archives>Archive Index >xsl-list Archive Home >Recent entries >Thread Prev - [xsl] targeting the last element in a node or consecutive elements [Thread Next] Re: [xsl] targeting the last element in a node or consecutive elementsTo: Date: 1/4/2007 2:53:00 PM Hi Emily, This is a double post, you already opened this discussion under "suppressing only the last PI" (which differed in details, however). If I may, it appears that you want to do this: <somenode> <node1 /> <?instr1?> <node2 /> <?instr2?> <?instr3?> </somenode> 1. Process node1, instr1, node2 etc 2. Do something before instr2 and instr3 (being consecutively and together at the end of a node) 3. Process instr2 and instr3 (if instr2 and instr3 were not there, you want to skip processing step 2 and 3?) Am i right? Please confirm (and/or give your sample input, to make the subject easier) Cheers, -- Abel Emily.Garrett@xxxxxxxxxxx wrote: I'm trying to use xsl:apply templates to grab the entire content of a node, except for any PIs that may be at the very end of the node. I can see how position()=last() can be used to refer to the very last PI, but how would I refer to possibly 2 or 3 PIs that are at the end of the node (not knowing what they are or how many), but still process PIs that are contained elsewhere in this content? Is there some syntax that refers to consecutive elements or refers to an element that is the last one in a node, not knowing what element it is? Here is explanation for what I'm trying to do: Process all content, unless they are PIs that occur consecutively at the very end of the node. Then I have to insert an element, then process these PIs that occur consecutively at the very end of the node. I'm having trouble narrowing down my research on this one. Does anyone have any ideas? Thanks, Emily | ||||||
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