Try



concat(document('index.xml')/protest/package/name, '.xml')



Spencer



On 12/4/06, chun ji <cji_work@xxxxxxxxx> wrote:
I have an index.xml file, which reads as:
"
-<?xml version="1.0" encoding="ISO-8859-1" ?>
-<?xml-stylesheet href="rules.xsl" type="text/xsl"?>
-<protest>
    -<package>
           -<name>billing</name>
      -</package>
     -<package>
           -<name>timecard</name>
      -</package>
-</protest>
".
There is a group of child xml files that associated
with each "/protest/package/name", such as
"billing.xml", "timecard.xml".

Now I have soming in my XSL file that tries to open
all these CHILD xml files,
"
<xsl:for-each
select="document(document('index.xml')/protest/package/name)">

</xsl:for-each>
"
which fails, because I did not give ".xml" for each
child xml.

Does someone know the format to do it ?




thanks a lot




cji









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