Altova Mailing List Archives>Archive Index >xsl-list Archive Home >Recent entries >Thread Prev - >Thread Next - Re: [xsl] Removing the extra elements through template match [xsl] Removing the extra elements through template matchTo: Date: 11/2/2006 12:37:00 PM How to remove the extra elements thru template match Hi All, I need help in resolving the problem for the below. I am using XSLT 1.0. Any suggestions are welcome. XML File <?xml version="1.0" encoding="UTF-8"?> <aaxml> <item name="control"> <envelope> <try_id>Sample</try_id> <rec_no>2006092405020001815466</rec_no> <selector_code>2071</selector_code> </envelope> </item> <item> <story> <rec_no>2006092405020001815466</rec_no> <try_id>AP ONLINE</try_id> <selector_code>2071</selector_code> <slug>Sample</slug> <story_number>V7193</story_number> <requested_action>ADD</requested_action> <headline>Sample text</headline> <byline>s</byline> <dateline>a</dateline> <dateline1>b</dateline1> <dateline2>Co</dateline2> <timestamp>09/24/06 05:02</timestamp> <time_zone>EDT</time_zone> <story_text>"<p>This is a sample text.</p>"</story_paragraph> <language>ENGLISH</language> <anpa_cat>s</anpa_cat> <update_timestamp>Sep 24 2006 5:04:00:000AM</update_timestamp> <sri_id>Sample</sri_id> </story> <subject> <subject_code>SELECTOR</subject_code> <subject_value>2071</subject_value> </subject> </item> </aaxml> XSL File <?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" encoding="utf-8" omit-xml-declaration="yes" indent="yes"/> <xsl:template match='story'> <rss version="2.0"> <channel> <title><xsl:value-of select="try_id"/></title> </item> </channel> </rss> </xsl:template> </xsl:stylesheet> Question: I don't want to display other than story element. How to give it in the xsl in a single command for the removing the irrespective of the tags not mentioned. Regards Srinivas | ||||||
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