There's a vast amount of flexibility in xsl:number, it's worth reading up on
the instruction. You can achieve this kind of thing quite easily by writing
count="e|f|g". 

Michael Kay
http://www.saxonica.com/



> -----Original Message-----
> From: Jonathan Marenus [mailto:jonathanmarenus@xxxxxxxxx] 
> Sent: 03 October 2006 03:32
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] new increment question
> 
> 
> Michael's previous answer helped a lot.  Thanks.
> 
> The functionality I would like to achieve now is similar to 
> the first.  The updated XML structure is the following:
> 
> <a>
>   <b>
>     <c>
>       <d>
>          <e/>
>          <f/>
>          <g/>
>       </d>
>     </c>
>     <c>
>       <d>
>          <e/>
>          <f/>
>          <g/>
>       </d>
>     </c>
>   </b>
>   <b>
>     <c>
>       <d>
>          <e/>
>          <f/>
>          <g/>
>       </d>
>     </c>
>     <c>
>       <d>
>          <e/>
>          <f/>
>          <g/>
>       </d>
>     </c>
>   </b>
> </a>
>    
> Here, I would like to output an incremental value for each e,f, or g.
> 
> In the case above,
> 
> first e: 1
> first f: 2
> first g: 3
> second e: 4
> second f: 5
> second g; 6
> 
> There will be situations where not all three elements
> (e,f,g) are within d.
> 
> So if there is only e in the first d and e,g in the second d, 
> the desired output will be:
> 
> first e: 1
> second e: 2
> g: 3
> 
> The output value should reset to 1 for every new a encountered.
> 
> Thank you.
> 
> Jonathan Marenus
> 
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