The stylesheet you are using calls msxsl:node-set(), which is a
vendor-specific extension function for the MSXML processor, but you are
running it (judging by the familiar error message) using Saxon.

I can't actually see why the stylesheet needs to call msxsl:node-set(). In
the construct

<xsl:value-of select="msxsl:node-set($theResult)"/>

$theResult is a result-tree-fragment; msxsl:node-set() is converting it to a
node-set, and xsl:value-of is then converting the node-set to a string. I
think this always gives the same result as converting the
result-tree-fragment directly to a string, which you can write as
<xsl:value-of select="$theResult"/>

Michael Kay
http://www.saxonica.com/
 

> -----Original Message-----
> From: LINKE Markus [mailto:markus.linke@xxxxxxxx] 
> Sent: 03 October 2006 22:47
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] XML Question
> 
> I've tried it but I receive an:
> 
> SystemID: xxx.xsl
> Location: 98:0
> Description: The URI urn:schemas-microsoft-com:xslt does not 
> identify an external Java class
> 
> error message at this location:
> 
>       </xsl:variable>
>       <xsl:value-of select="msxsl:node-set($theResult)"/> 
> <!-- here -->
>    </xsl:template>
> 
> ???
> 
> Thanks for your help!
> Markus
> 
> ----- Dimitre Novatchev <dnovatchev@xxxxxxxxx> wrote:
> > You need to apply this code:
> >    http://www.topxml.com/code/default.asp?p=3&id=v20010323001030
> > 
> > to all leaf nodes in the tree.
> > 
> > 
> > 
> > --
> > Cheers,
> > Dimitre Novatchev
> > ---------------------------------------
> > Truly great madness cannot be achieved without significant 
> > intelligence.
> > ---------------------------------------
> > To invent, you need a good imagination and a pile of junk
> > -------------------------------------
> > You've achieved success in your field when you don't know 
> whether what 
> > you're doing is work or play
> > 
> > 
> > 
> > On 10/3/06, LINKE Markus <markus.linke@xxxxxxxx> wrote:
> > > this might be the better audience ...
> > >
> > > ----- LINKE Markus <markus.linke@xxxxxxxx> wrote:
> > > > Hi,
> > > >
> > > > I am not sure if this is the right list for such a question, but
> > lets
> > > > try :)
> > > >
> > > > I would like to create a list of xpaths via xsl from a given 
> > > > xml-structure like this:
> > > >
> > > > <a>
> > > >    <b>
> > > >       <c>
> > > >          content
> > > >       </c>
> > > >       <d>
> > > >          morecontent
> > > >       </d>
> > > >    </b>
> > > > </a>
> > > >
> > > > it should show the full xpath like
> > > >
> > > > a/b/c  ====>   content
> > > > a/b/d  ====>   morecontent
> > > >
> > > > and not just
> > > >
> > > > c => content
> > > > d => morecontent
> > > >
> > > > Ideas anyone? I am looking for either a script or some xsl ...
> > > >
> > > > Cheers,
> > > > Markus