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On 1 Aug 2006 at 16:48, Cailo wrote:
> My problem is that because memberOf is an array within AD, the query is
> only searching the first 'string' of the array and hence not returning
> correct results. What I would like to do is to either query the entire
> array or join each string within the array to create one long string,
> then query the string. Please see below my script:
>
> <xsl:template match="rf:attr[@name='memberOf']">
> <attr name="GroupID">
> <value>
> <xsl:variable name="group" select="*" />
> <xsl:choose>
> <xsl:when test="contains($group,'Group_1')">100663298</xsl:when>
> <xsl:when test="contains($group,'Group_2')">100663299</xsl:when>
> <xsl:otherwise><xsl:value-of select="100663296" /></xsl:otherwise>
> </xsl:choose>
> </value>
> </attr>
> </xsl:template>
It's not clear to me whether $group is populated with a string or a
node set. Contains() always verifies the existence of a substring
within another string; it's not, as Michael Kay pointed out in other
words, an equivalent of PHP's in_array() or JavaScript's "if (var
prop in obj)".
> I have done this previously with javascript and it worked fine however I
> am unable to get this to work. Please see below the javascript:
>
> Dim strGroups
> If IsArray(varProp) Then
> strGroups = (Join(varProp))
> If (InStr(strGroups, "CN=Group_1") > 0 ) Then
> objUser.IsUnprotected = 0
> objUser.GroupID="Orlando"
> End If
> End If
I imagine you mean the above is pseudo-code for your actual
JavaScript. Well, JavaScript is a *very* different animal from XSLT.
Anyway, in the bit of code above it seems that you're checking for
the existence of "CN=Group_1" within strGroups, which in turn seems
to be the result of the concatenation of all varProps. This can be
done in XSLT; perhaps your problem is that you're doing something
wrong when trying to concatenate all the strings.
As for using a node set as a kind of array and checking for the
existence of the desired substring in the text value of each node (in
this case, the equivalent of an array element), you need a mechanism
to cicle through all the nodes in the node set (all the "elements" in
the "array"). Otherwise, only the first node will be checked.
To do that, you'll need a recursive template, i.e. a template that
calls itself until all the nodes in the node set have been checked.
Here's a very simple example, just so you can understand the idea:
==============
test.xml
---------------------------
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="test.xsl"?>
<root>
<array>
<elem key="0">apple</elem>
<elem key="1">banana</elem>
<elem key="2">cherry</elem>
<elem key="3">orange</elem>
<elem key="4">raspberry</elem>
<elem key="5">watermelon</elem>
</array>
<search>
<item>banana</item>
<item>orange</item>
</search>
</root>
==============
==============
test.xsl
---------------------------
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.w3.org/1999/XSL/Transform
http://www.w3.org/2004/11/schema-for-xslt20.xsd">
<xsl:output method="html" indent="yes" encoding="utf-8"/>
<xsl:template match="/">
<html>
<head>
<title>Results</title>
</head>
<body>
<xsl:apply-templates select="//search"/>
</body>
</html>
</xsl:template>
<xsl:template match="search">
<xsl:call-template name="in-array">
<xsl:with-param name="haystack" select="/root/array/elem"/>
<xsl:with-param name="needle" select="item"/>
</xsl:call-template>
</xsl:template>
<xsl:template name="in-array">
<xsl:param name="haystack"/>
<xsl:param name="needle"/>
<xsl:if test="$haystack and $haystack[1]">
<xsl:if test="$needle = $haystack[1]">
<p>Match: item <xsl:value-of select="$haystack[1]/@key"/></p>
</xsl:if>
<xsl:call-template name="in-array">
<xsl:with-param name="haystack" select="$haystack[position() >
1]"/>
<xsl:with-param name="needle" select="$needle"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
==============
My apologies if I misunderstood the nature of your problem. And
although I believe the example above can help you solve your problem,
it's possible that my preceding considerations are not entirely
accurate. I'm not Michael Kay! ;o)
Erik
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