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Re: [xsl] Having Trouble With Condition For Default Nodeset Selection

From: "G. Ken Holman" <gkholman@-------------------->
To:
Date: 7/5/2006 12:22:00 AM
In your case, using the not() in the predicate
will be true for those members that are not the
value of the country code, therefore it will be
true for many members.  So, you need a predicate
that will only be true when the member is not found.

I think I would use something along the lines of:



<!--are you sure you need "//" in the following?-->
<xsl:variable name="codes"
              select="$currency-data//currency"/>
<xsl:variable name="found-code"
              select="$codes[@code = $country-code]"/>
<xsl:variable name="currency"
              select="$found-code |
                      $codes[@code='US'][not( $found-code )]"/>

I hope this helps.



. . . . . . . . . Ken



At 2006-07-05 09:57 +1000, Duncan Anker wrote:
I am trying to look up a country code in a list
of supported currencies, with a default to US if
it is not found. I am using the XSLT 1.0 idiom of

nodeset1[condition] | nodeset2[not(condition)]



for a mutually exclusive result, however for the
life of me I can't seem to find a suitable
condition - I probably just need a figurative
whack on the side of the head to help me "think
different" (or should that be "differently?"). I
have tried several different variations of the
following with no luck, though I am probably
just overlooking something really obvious:

<xsl:variable name="currency"
select="$currency-data//currency[@code=$country-code
and @code != 'US'] |
$currency-data//currency[not(@code=$country-code and @code != 'US')]" />

Nothing seems to work no matter how I arrange
that - the US currency is always unioned into
the set. I'm sure that's the wrong condition to
use, and there is something relatively simple I
can add, but I'm just not seeing it.

Does anyone have any suggestions, or perhaps a nerf mallet?

:{)}




--
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