Altova Mailing List Archives>Archive Index >xsl-list Archive Home >Recent entries >Thread Prev - [xsl] Counting total of groups [Thread Next] Re: [xsl] Counting total of groupsTo: Date: 6/1/2006 10:53:00 AM Ohh, was simpler that I was trying to do incrementing a variable. Anyway, I have seen some examples and some e-mails on the list regarding to how increment a variable and If I'm not wrong there is no possibility of incrementing inside a for-each loop, so sometimes you need to change the xsl code only to make this feature working. I have seen that in XSLT 2.0 we have an incremental function but I'm a newbie even in XSLT 1.0 so do you recommend to use version 2.0 instead of 1.0? Does this version a lot of improvements against version 1.0? Anyone have a good and very simple example, a link or something that explains this "problem"? Regards Francisco David Carlisle wrote: I need to have that the number of groups is 3. which is the number of things selected by <xsl:for-each select="product[count(. | key('hotelname', name)[1]) = 1]"> so <xsl:variable name="grps" select="product[count(. | key('hotelname', name)[1]) = 1]"> no of groups is <xsl:value-of select="count($grps)"/> <xsl:each select="$grps"> .... or, if you only need the number withing the for-each you don't need to count you can use last() like: <xsl:for-each select="product[count(. | key('hotelname', name)[1]) = 1]"> group <xsl:value-of select="position()"/> out of <xsl:value-of select="last()"/> ... David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________ Chasetravel.ie, Winner ITTN Awards 2005. "Best Hotel Booking Engine" | ||||||
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