David,

Below is the XSLT that I am currently trying to use. The portion  
above the first comment creates the structure that I want except that  
it doesn't include the <Root> element that the <Story> element is  
contained in. Then when I add the instructions below the first  
comment to try to rename the elements, I lose the structure and tags  
that I want. My XML file structure is as such:



<Root>
	<Story>
		<articleTitle>Content</articleTitle>
		<articleSubTitle>Content</articleSubTitle>
		<author><authorFname>content</authorFname></author>

This is my stylesheet:



<xsl:template match="Story">

       <xsl:copy>

       <BB><TG>

<xsl:apply-templates select="articleTitle|articleSubTitle"/>

       </TG></BB>

       <xsl:apply-templates select="*[not(self::articleTitle or  
self::articleSubTitle)]"/>

       </xsl:copy>

  </xsl:template>

<!--Above this line creates the directory structure that I need-->

    <xsl:template match="Root">

        <DG>

            <xsl:apply-templates select="@*|node()"/>

        </DG>

    </xsl:template>

    <xsl:template match="Story">

        <D>

            <xsl:apply-templates select="@*|node()"/>

        </D>

    </xsl:template>



<chad/>



Chad Chelius
AGI Training
cchelius@xxxxxxxxxxxxxxx


On Jun 1, 2006, at 12:05 PM, David Carlisle wrote:



I need all of the other elements to come over as
well and I need to rename those elements.
yes that's what the
 <xsl:apply-templates select="*[not(self::title or self::subtitle)]"/>
is doing, applying your templates to all the child elements.
Sounds like you don't want document to go to document though so change
 <xsl:copy>  to <D>

and when I said



you just need a standard identity template,
read that as "you just need the templates doing whatever  
transformation

they are doing"



David