In XPath 1.0 there is no way of constructing a sequence of strings (there's
no such type in the data model), and there is no way of constructing new
nodes, so I'm afraid this is impossible.

In 2.0 it's straightforward:

for $x in (your current expression)
return substring-after($x, '(mm)')

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: Dariusz Borowski [mailto:d.borowski@xxxxxx] 
> Sent: 02 March 2006 00:59
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Expression in XPath
> 
> Hi!
> 
> Could anyone help me? I have this result:
> ========================================================
> (mm)B-1: A eTSS Login
> (mm)B-2: A eLogbook Viewer Login
> (mm)B-3: A Rig Activity Entry (Req. # 6.2.2.1.1, 6.2.2.3.5, 3.5.1.1)
> (mm)B-4: A Access tool from PC outside the firewall in SCTF 
> (mm)B-5: A eReport Login
> (mm)B-6: A Privileged User ? Login
> ========================================================
> 
> from this expression:
> //office:body/office:text/table:table/table:table-row/table:ta
ble-cell/text:p[starts-with(text(), '(mm)')]
> 
> 
> But, I would like to get the following result with ONE Expression:
> ========================================================
> B-1: A eTSS Login
> B-2: A eLogbook Viewer Login
> B-3: A Rig Activity Entry (Req. # 6.2.2.1.1, 6.2.2.3.5, 3.5.1.1)
> B-4: A Access tool from PC outside the firewall in SCTF 
> B-5: A eReport Login
> B-6: A Privileged User ? Login
> ========================================================
> 
> I tried already something like this:
> //office:body/office:text/table:table/table:table-row/table:ta
ble-cell/text:p[substring(starts-with(text(), '(mm)'), 4)]
> 
> but it didn't work... :(
> 
> Thanks for any help!
> 
> Dariusz
> 
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