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Re: [xsl] Copy-of & New Namespace prefix

From: George Cristian Bina <george@------------->
To:
Date: 2/1/2006 3:53:00 PM
Hi Christopher,



Your expected output is not XML as the prefix foo is not bound.

If for instance foo points to the http://www.example.com/foo then the 
following stylesheet will do what you want:



<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"

  xmlns:foo="http://www.example.com/foo">

  <xsl:template match="node() | @*">

    <xsl:copy>

      <xsl:apply-templates select="node() | @*"/>

    </xsl:copy>

  </xsl:template>

  <!-- matches elements -->

  <xsl:template match="*">

    <!-- creates an element with the same local name but in the foo 
namespace-->

    <xsl:element name="foo:{local-name()}" 
namespace="http://www.example.com/foo">

      <xsl:apply-templates select="node() | @*"/>

    </xsl:element>

  </xsl:template>

</xsl:stylesheet>




Best Regards,
George
---------------------------------------------------------------------
George Cristian Bina
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
www.---.com


Woods, Christopher wrote:
Hello,



I want to create a transform that takes an (X)HTML as an input and gives
back the unchanged but for the addition of a namespace prefix to each
element.  Input file might be as follows:

<html>
<body>
<p><b>Generalized foo here</b></p>
<ol>
<li>Foo 1</li>
<li>Foo 2</li>
</ol>
<p>Final foo</p>
</body>
</html>

Output might be as follows:



<foo:html>
<foo:body>
<foo:p><foo:b>Generalized foo here</foo:b></foo:p>
<foo:ol>
<foo:li>Foo 1</foo:li>
<foo:li>Foo 2</foo:li>
</foo:ol>
<foo:p>Final foo</foo:p>
</foo:body>
</foo:html>

My instinct say to use <xsl:copy-of> but I'm confused about how I might
add the prefix.  Thanks very much.


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