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Re: [xsl] foreach, preceding-sibling::node() and following-sibling::node()

From: "Mingqiang Yu" <myu@-------->
To:
Date: 11/1/2005 2:11:00 PM
Thanks a lot. I think I get it now.

Ming

>
> You have
>  <xsl:choose>
>     <xsl:when test="idlink">
>      <xsl:copy-of select="idlink[1]/preceding-sibling::node()"/>
>       <xsl:for-each select="idlink">
>
>
> That says, if the curent node has an idlink child anywhere, first copy
> all the children after the first idlink (including any later idlinks)
> then after that process all the idlink elements.
>
>
> You don't want to do that at all, you just want to process each element
> in the order it appears in the file, so replace all of the code you showed
> by a single
> <xsl:apply-templates/>
> then have a template for idlink that makes a link,as has been shown
> earlier.
>
> David
>
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