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![]() | ![]() | ![]() | Altova Mailing List Archives>Archive Index >xsl-list Archive Home >Recent entries >Thread Prev - >Thread Next - RE: [xsl] removing nodes according to attibute value RE: [xsl] removing nodes according to attibute valueTo: Date: 11/1/2005 9:32:00 PM Michael Kay:
> Start with an identity template that copies everything:
> <xsl:template match="*">
> <xsl:copy><xsl:copy-of
> select="@*"/><xsl:apply-templates/></xsl:copy>
> </xsl:template>
Or matching "node()" if you want to copy everything, isn't it?
<xsl:template match="node()">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
--drkm
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