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Re: [xsl] Processing IDREFS attributes

From: "G. Ken Holman" <gkholman@-------------------->
To:
Date: 11/1/2005 10:23:00 PM
At 2005-11-01 13:00 -0800, Dan Vint wrote:
I've got a few places where I have an attribute of type IDREFS and a 
sequence of ID values like references="Location Party Organization". 
I had thought a simple for-each loop would pull these apart with the 
id() function, in something like this:



<xsl:for-each select="id(@references)">
        <xsl:value-of select="."/>
</xsl:for-each>

Close ....



But it doesn't work. What I get is the content of @references with the above.

Really?  I would have thought you'd get the concatenation of the 
element content of the referenced elements.



The only other solution I have thought about is creating a template 
and recursively pulling apart the string. This should work, but I 
would think there is a simpler way to make this work. Is there a 
solution I missed?

*If* you have properly declared the id attributes, for my example 
they are called id=, something along the lines of:



  <!ATTLIST foo id ID #IMPLIED>



then you should be able to say:



  <xsl:for-each select="id(@references)/@id">
    <xsl:if test="position()>1"> </xsl:if>
    <xsl:value-of select="."/>
  </xsl:for-each>

and it would report a space-separated list of unique token values 
(rather than just @references since that might have duplicates).



If you don't have a declaration of the attribute type, then id() has 
nothing to look up and will always return an empty node set.



I hope this helps, Dan.



. . . . . . . . . Ken



--
World-wide on-site corporate, govt. & user group XML/XSL training.
G. Ken Holman                 mailto:gkholman@xxxxxxxxxxxxxxxxxxxx
Crane Softwrights Ltd.          http://www.CraneSoftwrights.com/s/
Box 266, Kars, Ontario CANADA K0A-2E0    +1(613)489-0999 (F:-0995)
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