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![]() | ![]() | ![]() | Altova Mailing List Archives>Archive Index >xsl-list Archive Home >Recent entries >Thread Prev - RE: [xsl] removing nodes according to attibute value [Thread Next] Re: [xsl] removing nodes according to attibute valueTo: Date: 11/1/2005 11:32:00 PM On 11/1/05, Michael Kay wrote: > > Michael Kay: > > > Start with an identity template that copies everything: > > > <xsl:template match="*"> > > > <xsl:copy><xsl:copy-of > > > select="@*"/><xsl:apply-templates/></xsl:copy> > > > </xsl:template> > > Or matching "node()" if you want to copy everything, isn't it? > > <xsl:template match="node()"> > > <xsl:copy> > > <xsl:copy-of select="@*"/> > > <xsl:apply-templates/> > > </xsl:copy> > > </xsl:template> > Your version will copy comments and processing instructions, > mine won't. Yes. It's what I meant (by "everything"). But you're right, it's not relevant to the OP problem. --drkm | ![]() | ![]() | ![]() |
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