Are you getting "First Pdf File". If so can you tell me if you are using
<xsl:value-of select="b/c[attribute::type='pdf'][1]"/> or anything else.

-----Original Message-----
From: omprakash.v@xxxxxxxxxxxxx [mailto:omprakash.v@xxxxxxxxxxxxx]
Sent: Friday, 2 September 2005 1:53 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Extract First node







Hi,
      It works correctly for me with saxon8.4.

cheers,
prakash







                      "SINGH Navpreet"

                      <Navpreet.SINGH@         To:
<xsl-list@xxxxxxxxxxxxxxxxxxxxxx>

                      Tenix.com>               cc:      (bcc:
omprakash.v/Polaris)

                                               Subject: [xsl] Extract
First node
                      09/02/2005 05:53

                      AM

                      Please respond

                      to xsl-list









Hi
I am having a problem with XPath expression for XSLT. I am trying to
extract a node from xml with a special attribute. For example
<a>
  <b>
    <c type="html">HTML file</c>
  </b>
  <b>
    <c type="text">Text File</c>
  </b>
  <b>
    <c type="pdf">First Pdf File</c>
  </b>
  <b>
    <c type="pdf">Second Pdf File</c>
  </b>
  <b>
    <c type="rtf">Rtf File</c>
  </b>
</a>

Element <c> can appear in any order and there could be a number of <c>
with
attribute type="pdf". I want to extract the first occurence of the
element
<c> which has a attribute type="pdf". I tried to extract it with
<xsl:value-of select="b/c[attribute::className='pdf'][1]"/>
after matching the template for <a>. But I am getting "First Pdf File
Second Pdf File". Can anyone tell me where I am making mistake. I am
using
Saxon-B8.5.
Thanks
Navpreet.





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