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Re: [xsl] Generating table cells and rows

From: David Carlisle <davidc@--------->
To:
Date: 8/1/2005 10:35:00 AM

> I would like to know if there is a way to do this with a table? Is it
> possible to output 5 table cells and add another <tr> tag if required

Don't think in terms of tags, XSLT can not process tags.
You want to generate a row every 5 nodes, and within that row process
the current node and its four next siblings:

<xsl:template name="displayPhotos">
<xsl:for-each select="$currentNodes[position() mod 5 = 1"> 
<tr>
<xsl:for-each select=".|following-sibling::*[position()&lt;4]">
  <img src="{$photo_server}/?studentId={id}"/><br /> Name: <xsl:value-of select="name"/>
</xsl:for-each>
</tr>
</xsl:for-each>
</xsl:template>

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