Clemens,



You could use keys to identify the elements to output.  Thus, your input:



<root>
	<sub_a>
		<elem_1/>
		<elem_2/>
		<elem_3/>
	</sub_a>
	<sub_b>
		<elem_1/>
		<elem_2/>
		<elem_2/>
		<elem_2/>
		<elem_3/>
	</sub_b>
	<sub_c>
		<elem_1/>
		<elem_2/>
		<elem_3/>
	</sub_c>
</root>

Against this transform:



<?xml version="1.0" encoding="iso8859-1"?>

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">



   <xsl:output method="xml" indent="yes"/>
   <xsl:strip-space elements="*"/>

   <xsl:key match="/*/*" name="kElems" use="*"/>



   <xsl:template match="root">
       <xsl:copy>
           <xsl:for-each select="*">
               <xsl:if test="count(key('kElems', .)) != count(*)">
                   <xsl:copy-of select="."/>
               </xsl:if>
           </xsl:for-each>
       </xsl:copy>
   </xsl:template>

</xsl:stylesheet>



Yields:



<?xml version="1.0" encoding="UTF-8"?>
<root>
 <sub_b>
   <elem_1/>
   <elem_2/>
   <elem_2/>
   <elem_2/>
   <elem_3/>
 </sub_b>
</root>

You could again use a key to identify and eliminate elements such as 
<elem_1>.  In fact *I* should do that, to match your required output ... but 
I need to use a composite key for that ... and it isn't coming to me right 
away.  If somebody else has more ready insight, please post.



Regards,



--A





From: "Prerovsky, Clemens" <Clemens.Prerovsky@xxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject: [xsl] only display if subnodes occur more than once
Date: Thu, 23 Jun 2005 12:06:42 +0200

Hi,



I'm stuck again with my XSL. My XML Structure looks like:



<root>
	<sub_a>
		<elem_1/>
		<elem_2/>
		<elem_3/>
	</sub_a>
	<sub_b>
		<elem_1/>
		<elem_2/>
		<elem_2/>
		<elem_2/>
		<elem_3/>
	</sub_b>
	<sub_c>
		<elem_1/>
		<elem_2/>
		<elem_3/>
	</sub_c>
</root>

The thing I want to do is display the element sub_b, because it has
subnodes which occur more than once (elem_2). I really have no idea how
to test for this - playing around for nearly two hours now. Im using a
loop like <xsl:for-each select="/root/*"> and the output should look
like

sub_b (this is the header)
elem_2
elem_2 (these are the 3 values of elem_2)
elem_2

Best regards,
Clemens Prerovsky

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