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[xsl] First Element in Sorted List

From: John <john-xsl-list@-------->
To:
Date: 6/1/2005 1:39:00 PM
I am hoping to to confirm something before going in the wrong direction.



My process needs to take action on the first element in a list of 
elements where the logic to determine first is the lowest numeric value 
of the sortorder attribute.  I don't believe there is a one-line way to 
do this - I believe the entire list must be sorted, and then the 
position of each element after sort compared to determine if it is first.



Is there a shorter/less expensive way to code the following



<xsl:for-each select="item">
  <xsl:sort select="@sortorder" data-type="number" />
  <xsl:if test="position() = 1">
    <!-- this is the first element in the sorted list -->
  </xsl:if>
</xsl:for-each>

I searched and found examples using this technique, but nothing really 
saying that this was the best or only approach.



Thanks in advance,



   -John


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