Hi Livio,
  I think this syntax will be required..
    <xsl:value-of select="A[@id='123']/B/@v"/>

You are using [@v] which is evaluation to a boolean

The expression: A[@id='123']/B[@v] is selecting B
nodes(which *have* v attribute) , which are child of A
nodes(whose id attribute has value 123).

And <xsl:value-of select="A[@id='123']/B[@v]"/> will
return the concatenated string value of such nodes.

Regards,
Mukul

--- dalloro@xxxxxxxxx wrote:
> Hi,
> 
> I'm a newby in XSL tranformations. I need to
> trasform an XML file into
> another XML file with a different structure.
> 
> Inside a template I build an element named Point
> that has several
> attributes. The value of one of these attributes
> depends on the value
> of an attribute in the source XML (the attribute v
> of the element B
> that I filtered through the parent 'id', in the code
> below)
> 
> [snip]
>    <xsl:element name="Point">
> [snip]
>       <xsl:attribute name="PointAttribute">
>         <xsl:value-of select="A[@id='123']/B[@v]"/>
>       </xsl:attribute>
> [snip]
>    </xsl:element>
> [snip]
> 
> I would like to obtain a 'Point' element with an
> attribute called
> 'PointAttribute' with the same value of the 'v'
> attribute of the
> element 'B'.
> 
> What is the best way to deal with this problem?
> 
> I thank you for the help.
> Best regards.
> 
> Livio.
> 
> 


		
__________________________________ 
Do you Yahoo!? 
Yahoo! Personals - Better first dates. More second dates. 
http://personals.yahoo.com