Hi,
     By "detailed navigational expressions" if you mean using indices like
[1], [2] etc in my xpath, I was only using it bcos I could be sure that
<root> will have a child named <tr> and <tr>, a child named <slideshow>
(just now realized).  However, I will try to follow your advise in future.

Cheers,
Omprakash.V











                                                                                                                   
                    "Michael Kay"                                                                                  
                    <mike@saxonic        To:     <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>                                 
                    a.com>               cc:     (bcc: omprakash.v/Polaris)                                        
                                         Subject:     RE: [xsl] namespaces in xslt                                 
                    04/01/2005                                                                                     
                    05:35 PM                                                                                       
                    Please                                                                                         
                    respond to                                                                                     
                    xsl-list                                                                                       
                                                                                                                   
                                                                                                                   




Your root element has only one child, it is a <tr> element. So root/*[2]
selects nothing. The <slideshow> is a child of the <tr>.

You seem to be trying to write detailed navigational expressions to reach
specific nodes in your source document. This isn't very robust, you will
have to make lots of changes when the source changes. It's much better to
write template rules to process each kind of element, and then recurse down
the tree using xsl:apply-templates.

Michael Kay
http://www.saxonica.com/



> -----Original Message-----
> From: omprakash.v@xxxxxxxxxxxxx [mailto:omprakash.v@xxxxxxxxxxxxx]
> Sent: 01 April 2005 12:54
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] namespaces in xslt
>
>
> Hi,
>         Iam having diffculty following what's happening:
>
> I have xml like this
>
> <table>
> <th>
> <root>
> <tr>
> <slideshow xmlns="urn:hl7-org/v3" title="Sample Slide Show"
> date="Date of
> publication" author="Yours Truly">
> <td><a href="file:///N65538"/>
> </td>
> </slideshow>
> </tr>
> </root>
> </th>
> </table>
>
>
> And my xsl:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0" xmlns:xsl
> ="http://www.w3.org/1999/XSL/Transform" xmlns="urn:hl7-org/v3" >
>
> <xsl:output method="xml" indent="yes" />
>
>    <xsl:template match="/">
>
>      <xsl:for-each select="//root/*[1]">
>      <xsl:copy>
>      <xsl:copy-of select="@*"/>
> <xsl:apply-templates select="@*|node()">
>           <xsl:with-param name="rootnode" select="$rootnode"/>
>      </xsl:apply-templates>
>      </xsl:copy>
>      </xsl:for-each>
>    </xsl:template>
>
> </xsl:stylesheet>
>
>
> When I select //own:root/*[1] in the <xsl:for-each>,  I get
> the following
>
> <?xml version="1.0" encoding="UTF-8"?>
> <tr xmlns="http://XYZ"/>
>
> but when I make it //root/*[2], I get nothing. But if you see, the
> slideshow is really at position 2 so I need to use 2.
>
>
> Cheers,
> Omprakash.V
>
>
>
>
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>
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