XPath 2.0 allows constructs of the form *:local which will match local in
any namespace, but there's no way of matching a set of namespaces.

I would recommend using a first transformation pass to normalize the
namespace URI, to keep this separate from the "real" transformation logic.
This is just a variant on the identity template:

<xsl:template match="one-uri:*">
  <xsl:element name="{local-name}" namespace="two-uri">
    <xsl:copy-of select="@*"/>
    <xsl:apply-templates/>
  </xsl:element>
</xsl:template>

Michael Kay 

> -----Original Message-----
> From: Mick Baggen [mailto:mick.baggen@xxxxxxxxxxxxxxx] 
> Sent: 01 July 2004 08:30
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] Wildcards in namespaces ?
> 
> Hello,
> 
> I would appreciate some help with the following problem:
> 
> I'm writing a XSLT stylesheet for processing of UML XMI files. Alas,
> depending on the UML tool, the elements in the XMI file are 
> placed in a
> different namespace. E.g. Poseidon (www.gentleware.com) uses the
> namespace-URI xmlns:UML = "org.omg.xmi.namespace.UML", and 
> Rational Rose
> uses xmlns:UML = "href://org.omg/UML/1.3". However, all of 
> them generate a
> prefix UML: for their XMI elements.
> 
> Now my problem is: how can I define a namespace in my XSLT 
> stylesheet so
> that I can process all XMI files with the SAME stylesheet ? I 
> came across a
> remark on the XSLT FAQ suggesting that it is possible to use 
> wildcards in
> the namespace, eg <xsl:stylesheet xmlns:UML="*UML*">. And 
> indeed, it seems
> that Xalan 2.6.0 recognizes this notation. However, libxslt 1.1.6
> (xmlsoft.org) does not.
> 
> I tried to look it up in the XSLT and XML Namespace 
> specifications, but I
> couldn't find whether this is valid. Could someone help me 
> out on this one ?
> If it is NOT valid XSLT, is there another way to achieve the 
> same result ?
> 
> Regards,
> 
> Mick Baggen
> Principal Consultant
> Technolution B.V.
> E-mail: 	 mick.baggen@xxxxxxxxxxxxxxx
> 
> 
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