It seems to be Xalan Java 2.4.1

version.JAXP=1.1
version.DOM=2.0
version.SAX=2.0
version.xalan2x=Xalan Java 2.4.1

Citando Michael Kay <mhk@xxxxxxxxx>:

> Questions about calling Java from XSLT are meaningless unless we know what
> XSLT processor you are using. The mechanisms vary from one XSLT processor to
> another.
>
> Michael Kay
>
> > -----Original Message-----
> > From: xptm@xxxxxxx [mailto:xptm@xxxxxxx]
> > Sent: 01 July 2004 14:10
> > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> > Subject: [xsl] Java namespace
> >
> > First, let me tell i'm not a expertise in these areas, so
> > bear with me...
> >
> > When i declare a namespace pointing to a Java class, is that
> > Java class treated
> > as a Static class? Or does the XSL processor somehow
> > instatiates a object of
> > that class?
> >
> > I'm asking this cause i have this situation:
> >
> > <?xml version="1.0" encoding="ISO8859-1" ?>
> > <xsl:stylesheet version="2.0"
> > 	xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
> >       	xmlns:gti = "SQLHelper" >
> >
> > (...)
> >             <xsl:element name="ResultSet">
> >       		  <xsl:attribute name="sql"><xsl:value-of
> > select="gti:AcertaSqlReservado($sql)"/></xsl:attribute>
> >             </xsl:element>
> >
> > This XSLT is called by a Java program
> >
> > public class Tester{
> >   public static void main(String[] args) {
> >     try {
> >       BufferedReader br = new BufferedReader(new InputStreamReader(new
> > FileInputStream(xin+".xml")));
> >       PrintWriter out = new PrintWriter(new
> > FileOutputStream(xout+".xml"));
> >       try {
> >         TransformerFactory xformFactory =
> > TransformerFactory.newInstance();
> >         Source xsl = new StreamSource("Testes12.xsl");
> >         Transformer stylesheet = xformFactory.newTransformer(xsl);
> >         Source request = new StreamSource(br);
> >         Result response = new StreamResult(out);
> >         //stylesheet.setParameter("gui", "awt");
> >         stylesheet.transform(request, response);
> >       }
> >       catch (TransformerException e) {
> >         System.err.println(e);
> >       }
> >     }
> >     catch (FileNotFoundException e) {
> >       System.err.println(e);
> >     }
> >   }
> >   }
> >
> > This works OK, but if i change the XSL to
> >
> > <?xml version="1.0" encoding="ISO8859-1" ?>
> > <xsl:stylesheet version="2.0"
> > 	xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
> >       	xmlns:gti = "Tester"   ---> the same Java class
> > that call the XSLT
> >
> > i got a TransformerException.
> >
> > But i don't understand why.
> >
> > Thanks all.
> >
> >
> >
> >
> >
> >
> > O SAPO j&#xE1; est&#xE1; livre de v&#xED;rus com a Panda Software, fique voc&#xEA; tamb&#xE9;m!
> > Clique em: http://antivirus.sapo.pt
> >
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O SAPO j&#xE1; est&#xE1; livre de v&#xED;rus com a Panda Software, fique voc&#xEA; tamb&#xE9;m!
Clique em: http://antivirus.sapo.pt