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[xsl] Retrieving the position of an ancestor in nested

From: "Jonny Pony" <jonnypony666@----------->
To:
Date: 5/4/2004 10:55:00 AM

Hi,



how can I retrieve the position of an ancestor in a nested 
<xsl:for-each>-loop?



My xml:



<?xml version="1.0" encoding="UTF-8"?>
<superNode>
	<Node>
		<SubNode>bla</SubNode>
		<SubNode>bla</SubNode>
		<SubNode>bla</SubNode>
	</Node>
	<Node>
		<SubNode>bla</SubNode>
	</Node>
	<Node>
		<SubNode>bla</SubNode>
		<SubNode>bla</SubNode>
	</Node>
	<Node>
		<SubNode>bla</SubNode>
	</Node>
</superNode>


The nested <xsl:for-each>:



<xsl:for-each select="Node">

	...

	<xsl:for-each select="SubNode">

		Position of Node: <xsl:value-of select="??????????"/> <!-- How will I get 
the position of the anchestor -->

		Position of SubNode: <xsl:value-of select="position()"/>

	</xsl:for-each>

</xsl:for-each>




Thanks
Jonny

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