Yes - I've got that in there. That's not the problem.

If we follow my <xsl:sort data-type="number" select="@page"/> line, my
output will be in this order:

   <question id="3" page="1"/>
   <question id="1" page="4"/>
   <question id="6" page="5"/>
   <question id="2" page="6"/>
   <question id="5" page="7"/>
   <question id="4" page="18"/>

Now - as I'm outputting the second item, I want to access the first one and
find out that its ID is "3". That's what I cant do.




-----Original Message-----
From: Rick Taylor [mailto:taylor@xxxxxxxx]
Sent: Tuesday, November 25, 2003 5:16 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] XSL - using for-each with sort - can't access
previous sorted nod e


Jeff,

Make sure that when you sort you specify the data-type
<xsl:sort select="@page" data-type="number"/>
or the 18 will come after the 1 and before the 2.

rick

At 04:45 PM 11/25/2003 -0500, you wrote:
>Hi all... just joined this list. Greetings :)
>
>I was wondering if someone might have an answer for me on this...
>
>Here's sample XML:
>
><quiz>
>    <question id="1" page="4"/>
>    <question id="2" page="6"/>
>    <question id="3" page="1"/>
>    <question id="4" page="18"/>
>    <question id="5" page="7"/>
>    <question id="6" page="5"/>
></quiz>
>
>In my XSLT, I want to sort by page. So I have:
>
><xsl:for-each select="question">
><xsl:sort select="@page"/>
>
>Now - as I am doing things to each question during the for-each, I want to
>be able to access the "id" attribute in the question outputted JUST PRIOR
to
>the one currently being outputted. I can't seem to be able to do this. I've
>tried using position() and <xsl:number> and combinations of the two, and
>have been unsuccessful. Could anyone give me some advice?
>
>Thanks,
>
>Jeff
>
>
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Rick Taylor
XML Developer
PPDM Association


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