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RE: [xsl] XSLT 2.0 and external parameters: a string -> xsd:integer. How?

From: "Michael Kay" <mhk@--------->
Date: 5/20/2003 11:54:00 AM
> I guess this is another angle on the typing questions that have been 
> floating around the list recently.
> Code that worked with Saxon 7.4 (and that I think would work 
> in XSLT 1.0) 
> is now broken with Saxon 7.5.
> How can I supply an external parameter to a Saxon 7.5 
> stylesheet which is 
> $number and has an integer value and get the XSLT processor 
> to treat it as 
> an xsd:integer. Well, I don't particularly want the parameter to be 
> xsd:integer but I assume I won't be able to do anything 
> numeric with it, 
> unless I make it explicitly numeric.

If you are passing parameters from a JAXP application, you can pass a
Java Integer.

If you want to do it from the command line, you can only pass strings;
you will have to convert the string to an integer within your own code
(this is exactly the same as writing a Java application that reads
arguments from the command line - they arrive as strings).
> If I try to ignore types altogether Saxon 7.5 complains, not 
> surprisingly, 
> that it cannot compare xsd:string to xsd:integer. If there is 
> a way to 
> write a type-agnostic stylesheet to accept a parameter that 
> is intended to 
> be numeric it isn't obvious to me at the moment.


<xsl:param name="p" as="xs:string"/>
<xsl:variable name="p-as-int" as="xs:integer" select="xs:integer($p)"/>

> So I made the input parameter xsd:string and created a new numeric 
> parameter using the xsd:integer() constructor function. Same 
> error message.
> Then I tried making the input parameter xdt:untypedAtomic with the 
> xsd:integer() constructor function to create the second 
> parameter.  Same 
> error message.
> Then I tried adding an as="xsd:integer". Same error message.

I'm afraid it's difficult to tell from this description exactly what you
did, and exactly what messages you got.
> The Saxon 7.5 documentation indicates that "most" such functions are 
> supported. Is this one unsupported or am I missing a basic 
> trick somewhere?

I think you missed a trick somewhere, but from the description I can't
tell where.

Michael Kay

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