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Re: [xsl] cannot transform to

From: Ryan Neil Gillespie <scoobie@-------->
To:
Date: 7/21/2002 2:18:00 PM
I think you want this instead for your stylesheet. Try it, but I'm new to
XSL.
-------------------------

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  version="1.0">
     <xsl:template match="/">
        <html>
          <xsl:attribute
name="xmlns">http://www.w3.org/1999/xhtml</xsl:attribute>
        </html>
     </xsl:template>
 </xsl:stylesheet>
----------------------

_ryan


On Sun, 21 Jul 2002, Phillip Rhodes wrote:

> Hi everyone,
> I created an xsl file that will generate an xhtml file.  With the xhtml
> file, I run it through an xhtml to fo converter (another xsl
> file  http://www.antenna.co.jp/XML/downfree/Xhtml2fo.xsl).
> My problem is that the xhtml to fo conversion does not work unless the html
> element appears as:
> <html xmlns="http://www.w3.org/1999/xhtml">
> </html>
>
> Unfortunately, my xhtml file's html element(after transformation) is:
> <html xmlns:html="http://www.w3.org/1999/xhtml">
> </html>
>
>
> I have the following stylesheet that does my transformation to xhtml:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
> xmlns:html="http://www.w3.org/1999/xhtml"
> version="1.0">
>     <xsl:template match="/">
>        <html>
>        </html>
>     </xsl:template>
> </xsl:stylesheet>
>
> It generates the following:
> <?xml version="1.0" encoding="UTF-8"?>
> <html xmlns:html="http://www.w3.org/1999/xhtml">
> </html>
>
> I want it to generate:
> <?xml version="1.0" encoding="UTF-8"?>
> <html xmlns="http://www.w3.org/1999/xhtml">
> </html>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

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