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Re: [xsl] generate-id() question

From: Joerg Heinicke <joerg.heinicke@------>
To:
Date: 6/3/2002 11:37:00 AM

nrashidi wrote:
Novice question...

I need to create links and i need the output of template match T to correspond 
to the ID values that are used in the href. I am not sure what needs to be put 
for the node-set argument of generate-id().



<xsl:for-each select="SEC">
 <a href="#{generate-id()}">

Hi Nick,



you only must find the way or XPath from SEC to T. Write this XPath in 
the paranthesis: generate-id(any/valid/XPath).



Regards,



Joerg



  <xsl:value-of select="."/>
 </a>
 <xsl:text/>
     <xsl:value-of select="following-sibling::*[1]"/><br/>
</xsl:for-each>
</xsl:template>

<xsl:template match="T">
     <a name="{generate-id()}"><xsl:value-of select="."/></a><br/>
</xsl:template>

Thanks
Nick




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