Joerg,

Once again, I really appreciate your help.  The problem isn't solved yet,
but I think it's because I oversimplified my original explanation and code.

Here's a better simplified version of my xhmtl file:

<table>
   <tr>
 	<td>
 	   <ol>
 		<li>item 1</li>
 		<li class="mgronly">item 2</li>
 		<li>item 3</li>
 	   </ol>
 	</td>
   </tr>
 
   <tr>
 	<td>
 	   <ol start="var">
 		<li>item 4</li>
 		<li>item 5</li>
 		<li>item 6</li>
 	   </ol>
 	</td>
   </tr>
</table>

I am transforming this document into two different documents by using two
different xsl files.  The first xsl file simply copies everything:

<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xhtml="http://www.w3.org/1999/xhtml"
    version="1.0">

<xsl:output method="xml" encoding="UTF-8"/>

<xsl:template match="node() | @*">
		<xsl:copy>
			<xsl:apply-templates select="node() | @*"/>
		</xsl:copy>
	</xsl:template>

</xsl:stylesheet>


The second xsl file filters out any <li> item with a class of "mgronly":

<?xml version="1.0" encoding="UTF-8"?>

<xsl:stylesheet
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xhtml="http://www.w3.org/1999/xhtml"
    version="1.0">

<xsl:output method="xml" encoding="UTF-8"/>

<xsl:template match="node() | @*">
		<xsl:copy>
			<xsl:apply-templates select="node() | @*"/>
		</xsl:copy>
	</xsl:template>

<xsl:template match="xhtml:li[@class='mgronly']"/>

</xsl:stylesheet>

Here's what I'm trying to do:  In the first transformation, I need to
replace "var" in the second <ol> tag with "4".
In the second transformation, because one of the preceding <li> items is
filtered out, I need to replace "var" with "3".  (I don't need to have the
XSL files count the <li> items to compute the "4" and "3", unless it's very
easy.  I can just hard code "4" and "3".) Is there a way to do this?

Thanks again for all your help--

Kathryn

Date: Sat, 01 Jun 2002 01:34:52 +0200
From: Joerg Heinicke <joerg.heinicke@xxxxxx>
Subject: Re: [xsl] Can you pass a parameter from a stylesheet to the
resulting HTML 	file?

Hello Kathryn,

it's a bit difficult to see, what you are doing with your two 
stylesheets. In general you can do it in the following:

<xsl:template match="foo">
   <xsl:apply-templates select="bar">
     <xsl:with-param name="name-of-param" select="value-of-param"/>
   </xsl:apply-templates>
</xsl:template>

<xsl:template match="bar">
   <xsl:param name="name-of-param" select="default-value-of-param"/>
   <xsl:value-of select="$name-of-param"/>
</xsl:template>

If your stylesheet below runs on the XML below, you can do something 
like the following:

<xsl:template match="node() | @*">
   <xsl:copy>
     <xsl:apply-templates select="node() | @*"/>
   </xsl:copy>
</xsl:template>

<xsl:template match="ol">
   <ol start="{count(preceding::ol) + 1}">
     <xsl:apply-templates select="node() | @*"/>
   </ol>
</xsl:template>

Regards,

Joerg

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