Thanks for the answer.



Does XSLT processor modifies the DTD's present in the original 
input file?



How does the XSLT processor restores the default values present in 
the DTD in the input file?



-------
Tinku

On Wed, 01 May 2002 Michael Kay wrote :
XSLT doesn't generate a DTD for the result tree. It would serve 
no useful

purpose.



When you do a transformation, you typically have in mind the 
structure of

the XML you want to generate. If you want to validate that the 
result

document actually conforms to this structure, you can add a 
DOCTYPE

declaration to the output file using <xsl:output>. The 
responsibility of

producing output that is actually valid according to the target 
DTD falls

entirely on the stylesheet author.



Michael Kay
Software AG
home: Michael.H.Kay@xxxxxxxxxxxx
work: Michael.Kay@xxxxxxxxxxxxxx

> -----Original Message-----

> From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx

> [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx]On Behalf Of 
tinku

> Sent: 01 May 2002 07:40

> To: XSL-List@xxxxxxxxxxxxxxxxxxxxxx

> Subject: [xsl] DTD

>

>

> Hi,

>

>     XSLT is used to transform an input XML tree into a result 
XML

> tree. Input XML tree has a DTD on which it is validated. But 
when

> we transform an input XML tree, XSLT produces a new XML tree 
which

> is completely different from the input tree. I wonder, how 
XSLT

> generates a new DTD for that result tree?.

>

> Thanks.

> Tinku.

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