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[xsl] help

From: "Zoe" <zoe@------------>
To:
Date: 5/1/2002 11:58:00 AM
Hi, 
I want to display the specific service id="01"'s name. 
how can I approach this? The result will be 'My News'. 
does it have any condition that I can use? Thanks. 

<xsl:for-each select="dynamictree/category/service"....? >
<!-- serviceid =01, name="My News" -->
</xsl:for-each>

XML file: 
- <dynamictree version="1" statuscode="0" statusdesc="OK">
- <category id="1" name="Favorite">
- <service id="01" name="My News">
  <querykeyword id="7003" name="News USA" /> 
  <querykeyword id="7004" name="News Africa" /> 
  </service>
- <service id="02" name="My Stocks">
  <querykeyword id="7001" name="Stock Quotes" /> 
  </service>
  </category>
  </dynamictree>



 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


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