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Re: [xsl] xpath - how to return all nodes but the node matching avalue in an arbitrary tree?

From: Joerg Heinicke <joerg.heinicke@------>
To:
Date: 5/4/2002 9:39:00 AM

<xsl:param name="delete_id"/>
 <xsl:template match="/">
  <xsl:copy-of select="//category//artist[@id!=$delete_id]"/>
 </xsl:template>

You select all artist-elements, which don't have the $delete_id. This 
works for me.

But I think you want something different. Try a copy whith each node 
separately:



<xsl:param name="delete_id"/>



<xsl:template match="*|text()|@*">
  <xsl:copy>
    <xsl:apply-templates select="*[@id != $delete_id]|text()|@*"/>
  </xsl:copy>
</xsl:template>

This stylesheet would copy the complete input to the output.



A little change at the apply-templates removes the elements which should 
be deleted:



<xsl:apply-templates select="*[@id != $delete_id]|text()|@*"/>



Regards,



Joerg




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Re: [xsl] xpath - how to return all nodes but the node matching avalue in an arbitrary tree?