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Re: [xsl] To simulate SORT inside a xsl:choose condition

From: Joerg Heinicke <joerg.heinicke@------>
Date: 4/29/2002 11:33:00 PM
Hello Kumar,

it's not completely correct, what you wrote in your code. It has to be

<xsl:sort  order="ascending"  select="*[name()=$sortmethod]"/>.

This means: Sort all regions in the file by a element ('*'), whose name 
(e.g. 'city') is the same as specified in $sortmethod.



I have written XSL to display city, companyname in Table structure .based on the criteria node's sorting i will have to either sort the data by City or Comp_name 
when it appears for the first time ...

I tried this ..globally i did 
<xsl:variable name="sortmethod" select="//criteria/sortby">

SOmewhere down in my template where i write xsl:for i do this ....
<xsl:for-each select="//regions">
      <xsl:sort  order="ascending"  select="name()=$sortmethod"/>

Does that work??


XSL-List info and archive:


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