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Re: [xsl] divide info in several output files
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Date: 3/1/2001 6:39:00 AM
need to output a html with a few (10 i.e.) of this itens and a link to other page containing the next 10 and so on til the last page including the last 8 items. The quantity of items can be different from one xml file to another so no quantity-dependant-solution other half of question, sorry hit send button too early. if u pass the style sheet parameters as discussed in previous posting, u can always use just one xml file with all the articles, selectively displaying whatever range ( start and end / page). u can do some counting math to generate < a hrefs > with param passed in the url ( remember parameter passing may be dependant on the type of parser you are using) ex. <a href="whatever.com?start=1&end=9>back</a> <a href="whatever.com?start=20&end=29>next</a> or depending on how your xml file was arranged <a href="whatever.com?page=1>back</a> <a href="whatever.com?page3>next</a> as xsl allows you to do numbering and counting and such, i leave it to u to generate. once again there are stacks of other ways to do this, using xlink comes to mind ( then generate javascript or typical links with another stylesheet, etc ), this is just a humble start. cheers, jim XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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