The definition of "substitution group" is already recursive.
 
Michael Kay


  _____  

From: xmlschema-dev-request@w... [mailto:xmlschema-dev-request@w...] On
Behalf Of Bharath Kumar Reddy T
Sent: 29 January 2009 11:03
To: xmlschema-dev@w...; 'George Cristian Bina'
Cc: ashutosh_p@h...; ranjit@h...
Subject: Particle restriction validity (elements with substitution group
affiliation)


Hi..
 
According to the constraints for restriction of a type definition, in the
specification http://www.w3.org/TR/xmlschema-1/#cos-particle-restrict, it is
given that 
 
2.1 Any top-level element declaration particle (in R or B) which is the
<http://www.w3.org/TR/xmlschema-1/#class_exemplar> {substitution group
affiliation} of one or more other element declarations and whose
<http://www.w3.org/TR/xmlschema-1/#key-eq> .substitution group. contains at
least one element declaration other than itself is treated as if it were a
choice group whose  <http://www.w3.org/TR/xmlschema-1/#p-min_occurs> {min
occurs} and  <http://www.w3.org/TR/xmlschema-1/#p-max_occurs> {max occurs}
are those of the particle, and whose
<http://www.w3.org/TR/xmlschema-1/#particles> {particles} consists of one
particle with  <http://www.w3.org/TR/xmlschema-1/#p-min_occurs> {min occurs}
and  <http://www.w3.org/TR/xmlschema-1/#p-max_occurs> {max occurs} of 1 for
each of the declarations in its  <http://www.w3.org/TR/xmlschema-1/#key-eq>
.substitution group..
 
 
so, In the following schema, "d" of base is a choice of "d" and "c". and "C"
of derived is a choice of c and b. 
 
 
 
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
 <xs:element name="a" type="xs:anyType" substitutionGroup="b"/>
 <xs:element name="b" type="xs:anyType" substitutionGroup="c"/>
 <xs:element name="c" type="xs:anyType" block="substitution"
substitutionGroup="d"/>
 <xs:element name="d" type="xs:anyType"/>

 <xs:complexType name="base">
  <xs:sequence>
   <xs:element ref="d"/>
  </xs:sequence>
 </xs:complexType>

 <xs:complexType name="derived">
  <xs:complexContent>
   <xs:restriction base="base">
    <xs:sequence>
     <xs:choice>
      <xs:element ref="c"/>
     </xs:choice>
    </xs:sequence>
   </xs:restriction>
  </xs:complexContent>
 </xs:complexType>
 <xs:element name="doc" type="base"/>
</xs:schema>

 
 
My doubt: d --- choice of d and c.
                      should i take the above c as a choice of b and c again
recursively???
 
But spec. says that the top level element declaration (in R or B) only can
be considered as choice group. 
So, recursion will not be applied since C  is not referenced again in base
type.
 
 
Can you please tell me whether i should take the choice group recursively or
not???
 
 
Thanks and Regards,
Bharath.